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by Ozlemg » Fri Jun 03, 2011 4:36 am
In the xy-plane, the point (-2, -3) is the center of a circle. The point (-2, 1) lies inside the circle and the point (4, -3) lies outside the circle. If the radius r of the circle is an integer, then r =
A. 6
B. 5
C. 4
D. 3
E. 2.
Last edited by Ozlemg on Fri Jun 03, 2011 5:29 am, edited 1 time in total.
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by Frankenstein » Fri Jun 03, 2011 4:43 am
Hi,
Center of the circle is at(-2,-3).
(-2,1) is inside the circle. So distance between (-2,-3) and (-2,1) is less than r i.e 4<r
(4,-3) is outside the circle. So distance between (-2,-3) and (4,-3) is greater than r i.e 6>r
i.e. 4<r<6. So r=5.

Hence, B
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by vikram4689 » Fri Jun 03, 2011 6:39 am
Draw a rough figure.
Point that lies inside is at 4 unit distance & Point that lies outside is at 6 unit distance
Since radius is an integer only option left is 5. Hence r = 5.
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by cans » Sat Jun 04, 2011 8:40 am
a(-2,-3); b(-2,1); c(4,-3)
ab=4 and ac=6.
b lies inside and c lies outside
thus 6>r>4
or r=5 (using the options )
IMO B
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