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Multiples of 4 between 12 and 96

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Multiples of 4 between 12 and 96

by money9111 » Mon Feb 01, 2010 8:34 pm
How many multiples of 4 are there between 12 and 96, inclusive?

a. 21
b. 22
c. 23
d. 24
e. 25

didn't know where to begin with this one either... this is the last question out of my problem set that I did not get... if you'll notice there's a theme with the questions I've just posted... all the same topic... Exponents, Odds & Evens, Postives, Negatives, and Roots were all easy for me... ::sigh::

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by kabirmohammed » Mon Feb 01, 2010 8:44 pm
How many multiples of 4 are there between 12 and 96, inclusive?

a. 21
b. 22
c. 23
d. 24
e. 25

Multiples of 4 are : 12, 16, 20, 24, ........, 96
for a evenly spaced set: total no of terms = (last - first)/increment
= 96-12/4
= 21
as the question ask for inclusive = 21+1 =22
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by money9111 » Mon Feb 01, 2010 8:52 pm
ah ha... "Last-First/increment"... going in my notecards... thanks!
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by Cally627 » Sun Apr 29, 2012 9:22 am
quick question,

if the problem mentions "inclusive" - we add the 1.

large - small / 2 + 1


if the problem doesn't mention inclusive - do we not add the 1?

thanks.
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by LalaB » Sun Apr 29, 2012 9:53 am
Cally627 wrote:quick question,

if the problem mentions "inclusive" - we add the 1.

large - small / 2 + 1


if the problem doesn't mention inclusive - do we not add the 1?

thanks.
no.

as for the q. above it can be solved this way-

((96-12)/4) +1=22
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by vinokayal » Thu Sep 26, 2013 7:57 am
Where

First Term = 12

Difference = 4

Last Term = 96

As per the formula

a+(n-1)d

12+(n-1)4 = 96

(n-1)4 = 96-12

(n-1)4 = 84

n-1 = 84/4

n-1 = 21

n=22

12 + (
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by Brent@GMATPrepNow » Thu Sep 26, 2013 8:03 am
money9111 wrote:How many multiples of 4 are there between 12 and 96, inclusive?

a. 21
b. 22
c. 23
d. 24
e. 25
If you'd rather not memorize formulas, you can also try listing and looking for a pattern.
Let's list the multiples of 4 from 12 to 96 inclusive.

12 = 4(3)
16 = 4(4)
20 = 4(5)
24 = 4(6)
.
.
.
88 = 4(22)
92 = 4(23)
96 = 4(24)

As you can see, the number of multiples of 4 from 12 to 96 inclusive is equal to the number of integers from 3 to 24 inclusive.

Well, we know that the number from integers from x to y inclusive equals y - x + 1

So, the number of integers from 3 to 24 inclusive equals 24 - 3 + 1 = 22

Answer: B

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by [email protected] » Thu Sep 26, 2013 11:38 am
Hi All,

Certain versions of these questions can be solved by including (and then removing) elements to "round out" the math.

In this case, it would be pretty easy to count the multiples of 4 from 1 to 100: there are 25 of them......25(4) = 100

So, which multiples of 4 must we REMOVE from this group of 25?

We want 12 to 96, inclusive, so we should REMOVE: 4, 8, 100. That's 3 values.

25 - 3 = 22

Final Answer:B

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by Jeff@TargetTestPrep » Mon Dec 11, 2017 4:11 pm
money9111 wrote:How many multiples of 4 are there between 12 and 96, inclusive?

a. 21
b. 22
c. 23
d. 24
e. 25
We can determine the multiples of 4 from 12 to 96 (inclusive) by using the following formula:

(largest multiple of 4 - smallest multiple of 4)/4 + 1

(96 - 12)/4 + 1 =84/4 + 1 = 21 + 1 = 22

Answer: B

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