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Multiple of both 2 and 8

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by ramyaravindran » Thu Apr 15, 2010 10:38 am
If one number is chosen at random from the first 1000 positive integers what is the probability that the number chosen is a multiple of both 2 and 8?

A) 1/125

B) 1/8

C) 1/2

D)9/16

E)5/8
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Source: — Problem Solving |

by neoreaves » Thu Apr 15, 2010 10:44 am
IMO C

multiple of both 8 and 2 will be multiple of 8


in the first 1000 there are 1000/8 = 125 multiples of 8


thus 125/1000 = 1/8
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by eaakbari » Thu Apr 15, 2010 10:49 am
@Neoreaves

You mean B not C. Correct the answer is 1/8
Whether you think you can or can't, you're right.
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by neoreaves » Thu Apr 15, 2010 10:53 am
yes you are right ....thats such a silly mistake ...i hope i can avoid it on the real test
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