Stmt I
y = |x| + x
y is 0 if x is 0 or x<0
Stmt I
x<0
Exactly what we need => y is 0 since |x| = -x when x is negative i.e |x|+x = -x + x which is 0 when x is negative
SUFF
Stmt II
y<1
Since y is an integer therefore x is 0 or x<0
SUFF
Choose D
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cramya
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Back to the gmat land after a few weeks off. Hope I am not rusty....
Stmt I
y = |x| + x
y is 0 if x is 0 or x<0
Stmt I
x<0
Exactly what we need => y is 0 since |x| = -x when x is negative i.e |x|+x = -x + x which is 0 when x is negative
SUFF
Stmt II
y<1
Since y is an integer therefore x is 0 or x<0
SUFF
Choose D
Stmt I
y = |x| + x
y is 0 if x is 0 or x<0
Stmt I
x<0
Exactly what we need => y is 0 since |x| = -x when x is negative i.e |x|+x = -x + x which is 0 when x is negative
SUFF
Stmt II
y<1
Since y is an integer therefore x is 0 or x<0
SUFF
Choose D