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Mixtures

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Mixtures

by shrey2287 » Sun Oct 02, 2011 11:54 pm
Some part of a 50% solution of acid was replaced with an equal amount of 30% solution of acid. If, as a result, 40% solution of acid was obtained, what part of the original solution was replaced?

a 1/5
b 1/4
c 1/2
d 3/4
e 4/5
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by shankar.ashwin » Mon Oct 03, 2011 12:23 am
Ratio in which they are mixed :

(5/10 - 4/10) / (4/10 - 3/10) = 1:1

Therefore 1/2 the solution was replaced. C IMO
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