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MIXTURE FORMULA

Problem Solving — algebra and arithmetic
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by lawalx » Sun Nov 25, 2007 1:41 am
I used to knw a simple formula for solving 'mixture problems' - all one had to do was jst plug in the values. does ne1 know this formula. pls hlp.

regards

lawalx
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Source: — Quantitative Reasoning |
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Re: MIXTURE FORMULA

by gabriel » Sun Nov 25, 2007 3:00 am
lawalx wrote:I used to knw a simple formula for solving 'mixture problems' - all one had to do was jst plug in the values. does ne1 know this formula. pls hlp.

regards

lawalx
Its called alligation ... it helps a lot in solving Mixture related problems, its very easy to understand .. just Google it , you should get plenty of articles on it, if you don't understand them let me know.

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by xcise_science » Mon Nov 26, 2007 8:53 am
Hi, I got this from mgmat, its not really a formula, it involves drawing a table
I find it very useful and supereasy; just plug in your values and add!


Image
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by GMATDUD » Mon Dec 10, 2007 1:34 pm
gabrial,

trying to understand how to extend the formula to 3 solution mixture. I remember getting a question with 3 different fat contents mixed to to obtain a desired outcome.

any inputs with a 3 solution mixture problem

thanks
T
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by xcise_science » Mon Dec 10, 2007 8:09 pm
Hi,
I believe it should still work the same. You would just need to add an additional row & column for the extra item.
Is the question from any of the OGs?
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by GMATDUD » Mon Dec 10, 2007 10:14 pm
Can you demonstrate with an example? I did not understand that grid in the picture.

If you can solve a 2 solutions question , I will try and implement on a 3 sol mixture.
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by xcise_science » Tue Dec 11, 2007 7:54 am
Hi
I've attached 2 questions, hope its clear.

I couldn't find one with a 3 solution mixture.
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Mixture Formula from Kaplan

by Poornima » Thu Mar 20, 2008 4:56 pm
This was a formula I came across in Kaplan and it seems to work with all the mixture problems I have encountered so far.

(percent diff b/w the desired soln and the weaker soln) * (amt of weaker soln) = (percent diff b/w the stronger soln and the desired soln) * (amt of stronger soln)

Hope that helps!
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this might help you

by clarence57 » Sun Mar 30, 2008 7:32 am
p1v1=p2v2
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by pierce22884 » Fri Feb 19, 2010 5:59 pm
Poornima wrote:This was a formula I came across in Kaplan and it seems to work with all the mixture problems I have encountered so far.

(percent diff b/w the desired soln and the weaker soln) * (amt of weaker soln) = (percent diff b/w the stronger soln and the desired soln) * (amt of stronger soln)

Hope that helps!
Can you apply that to xcise_science work problems so that I can see exactly what your talking about.
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by shashank.ism » Sat Feb 20, 2010 11:15 am
xcise_science wrote:Hi, I got this from mgmat, its not really a formula, it involves drawing a table
I find it very useful and supereasy; just plug in your values and add!


Image
ACTUALLY IN THIS CASE YOU NEED TO SOLVE THE PROBLEM THIS WAY

(40 x x + 60 x y )/100
where x and y are the quantities in each and 40 and 60 represents the percentage....
I have found many problems related to mixture in various post....go through it ..it willl really help..
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