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Milk Man

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by mattocks » Sat Jul 24, 2010 6:47 am
A milkman adds 5 liters of water to a certain quantity of pure milk costing $3 per liter. He sells the mixture at the same price as before and makes a 20% profit. What is the percentage milk in the mixture?

A. 83.33
B. 93.33
C. 73.33
D. 55
E. 68
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by kvcpk » Sat Jul 24, 2010 6:55 am
mattocks wrote:A milkman adds 5 liters of water to a certain quantity of pure milk costing $3 per liter. He sells the mixture at the same price as before and makes a 20% profit. What is the percentage milk in the mixture?

A. 83.33
B. 93.33
C. 73.33
D. 55
E. 68
cost of m = 3 per lit
m +5 units present now.
m+5 units will generate (m+5)*3 dollars

If there was no water, he would have got 3m dollars.

Hence, (3m+15 - 3m)/3m * 100 = 20
5/m = 1/5
m = 25

Total mixture = 25+5 = 30
Percentag eof milk = 25/30 *100= 5/6 *100= 83.33

pick A
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by outreach » Sat Jul 24, 2010 8:05 am
(5+m)*3=(120/100)*3m
m=25

total milk=30
25 is 83.33 of 30
A
mattocks wrote:A milkman adds 5 liters of water to a certain quantity of pure milk costing $3 per liter. He sells the mixture at the same price as before and makes a 20% profit. What is the percentage milk in the mixture?

A. 83.33
B. 93.33
C. 73.33
D. 55
E. 68
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by indiantiger » Sat Jul 24, 2010 2:48 pm
let the quantity of milk be x

total earnings from milk after mixing water = price per ltr * (x+5)
total cost of getting x lts of milk = 3x

profit = 3(x+5) -3x
3x * 20/100 = 15
3x/5 = 15
x = 25

% of milk = 25/30 = .833 or 83.3%
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