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MGMAT Test q

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by badri077 » Sun Jul 29, 2007 11:31 pm
From one of the MGMAT Test qs
Any help would be appreciated. The answer explanation states that any triangle inscribed in a circle with base as diameter must be a right angled triangle. Not sure I agree with this.

Thanks,
-B
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Source: — Data Sufficiency |
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Re: MGMAT Test q

by gabriel » Mon Jul 30, 2007 1:02 am
badri077 wrote:From one of the MGMAT Test qs
Any help would be appreciated. The answer explanation states that any triangle inscribed in a circle with base as diameter must be a right angled triangle. Not sure I agree with this.

Thanks,
-B
.. well u have to agree with it ... it is not something the manhattan guyz have cooked up ... it is a well accepted theorem ... the theorem roughly states that any triangle drawn with the diameter as a base is a right angled triangle ..
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reg:

by badri077 » Mon Jul 30, 2007 10:08 pm
lol. thanks.
It's been a while since I've been out of college.
Any tips on which of the prep. material over this particular theorem ?
I've missed it in my re-reading so far..

thanks.
-B
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by induscrede » Wed Aug 01, 2007 12:06 am
its one of those theorems.. dunno how to prove it but its true :)
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The answer is C

by sumedh2221 » Fri Aug 03, 2007 10:03 pm
The answer is C , because from the statement B u can get circumference pie.D =18 implies D =18 . So line must be a diameter . Now use a it be comes 30 60 90 triangle
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