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Expert replies
by resilient » Mon May 26, 2008 5:38 pm
A clock store sold a certain clock to a collector for 20 percent more than the store had originally paid for the clock. When the collector tried to resell the clock to the store, the store bought it back at 50 percent of what the collector had paid. The shop then sold the clock again at a profit of 80 percent on its buy-back price. If the difference between the clock's original cost to the shop and the clock's buy-back price was $100, for how much did the shop sell the clock the second time?


$270
$250
$240
$220
$200

what is the nonalgebraic way to do this. I am backsolving but takes awhile. Any easier ways?

qa is 270
Last edited by resilient on Mon May 26, 2008 6:59 pm, edited 1 time in total.
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Source: — Problem Solving |

by aatech » Mon May 26, 2008 6:20 pm
Well, I see you are looking for non-algebrix way to solve this... IMO, algebric is straight forward and easy to calculate... Let me know if you want to know about my approach (algebric)

ANS is 250
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by resilient » Mon May 26, 2008 7:02 pm
Yes you are right. It is best to just assign the variables and then plow through.

However, you stopped one step too short and stopped at 250. If you look closely question asks what was the resell (1.08p) price. hence qa is 270.
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by aatech » Tue May 27, 2008 5:18 am
Ahh... big mistake.. thanks for correcting me
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