Median..

IMO A

tot no 100(assume)
40<40000
11=43000
5=49000
40>50000

median is avg of 50th and 51st

50th person earning is 43000
and 51st's earning is 43000

so med is 43000

OA pls

correct.could you please give a detailed explanation..?am getting stuck:(

I agree: 43k. 5% is not enough to modify the 50th and 51st value

uptowngirl92 wrote:correct.could you please give a detailed explanation..?am getting stuck:(

n a company 60% of the employees earn less than $50,000 a year, 60% of the employees earn more than $40,000 a year, 11% of the employees earn $43,000 a year and 5% of the employees earn $49,000 a year. What is the median salary for the company?
ASSUME TOTAL NO. AS 100

FROM THE INFO GIVEN
60 earn <50k => 40 earn more than 50k
60 earn >40k => 40 earn less than 40k
11 earn 43k
5 earn 49k

now make a no. line as given below:

---40<40k-----11=43k-------5=49k----40>50K------
we are left with 4 people that can be any where b/n 40k and 50k.
if it is b/n 40k and 43k then the value of 50th and 51st person will be 43000,and
if it is b/n 43k and 50k , then also value of 50th and 51st is 43k
now median of value of 100 item is median of of value of 50th and 51st item.i.e avg of 43000&43000
which is 43000.
HTH

the wordings of the q is making the thing a bit complicate ; but the key to solve this is just to find that what is the earning value for 50th and 51st person.