bharathaitha wrote:Tom, Jane, and Sue each purchased a new house. The average (arithmetic mean) price of three houses was $120,000. What was the median price of the three houses?

1. The price of Tom's house was $110,000
2. The price of Jane's house was $120,000

Here is my way:

Statement 1 --> (Given) mean(T+J+S) = 120k => T+J+S = 360k
as per stmt1, T=110k and here goes possible chances:
T J S Median
110 110 140 110
110 115 135 115
110 120 130 120 and so on..
Hence we cannot conclude the median..so this is insufficient.

Statement 2 --> Same this time with J..
T J S Median
115 120 125 120
119 120 121 120
120 120 120 120
So if T decreases, S increases, but J remains constant and so as the median. So this is sufficient.

My ans is B

I am also with B
since from B, its sure that one will be less than 120K and another greater than 120K
hence median will be 120K

or all 3 of them are 120K

hence B