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Medals are to be awarded to three teams in a 10-team competition. If one medal is gold, one medal is silver, and one

Expert replies
by BTGmoderatorDC » Sun Feb 02, 2020 7:08 pm
Medals are to be awarded to three teams in a 10-team competition. If one medal is gold, one medal is silver, and one medal is bronze, how many different ways are there to award the three medals to teams in the competition?

A. 10!/7!
B. 10!/(3!7!)
C. 10!/3!
D. 7!/3!
E. 7!/94!3!)



OA A

Source: Manhattan Prep
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Source: — Problem Solving |

BTGmoderatorDC wrote: ↑
Sun Feb 02, 2020 7:08 pm
Medals are to be awarded to three teams in a 10-team competition. If one medal is gold, one medal is silver, and one medal is bronze, how many different ways are there to award the three medals to teams in the competition?

A. 10!/7!
B. 10!/(3!7!)
C. 10!/3!
D. 7!/3!
E. 7!/94!3!)

OA A

Source: Manhattan Prep
• The gold medal can be awarded in 10 ways;
• The silver medal can be awarded in 9 ways; since one team already got gold.
• The bronze medal can be awarded in 8 ways; since two teams already got gold and silver.

Total no. of ways = 10*9*8; this can also be written as 10!/7!.

The correct answer: A

Hope this helps!

-Jay
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3 medals can be awarded to 10 teams in 10p3 ways (since order in in which medals is given matter)
thus 10p3= 10!/(10-3)! = 10!/7!.
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BTGmoderatorDC wrote: ↑
Sun Feb 02, 2020 7:08 pm
Medals are to be awarded to three teams in a 10-team competition. If one medal is gold, one medal is silver, and one medal is bronze, how many different ways are there to award the three medals to teams in the competition?

A. 10!/7!
B. 10!/(3!7!)
C. 10!/3!
D. 7!/3!
E. 7!/94!3!)



OA A

Source: Manhattan Prep
Since the order matters (i.e., who gets gold, who gets silver and who gets bronze matters), the number of ways that 3 teams can be chosen from 10 teams is:

10P3 = 10 x 9 x 8 = (10 x 9 x 8 x 7!)/7! = 10!/7!

Answer: A

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