Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

measurement

Expert replies
by romitvsingh » Fri Mar 23, 2012 11:09 pm
The curved surface of a cylinder is 264m^2.Its volume is 924m^3. The height of the cylinder must be

a 4m

b 6m

c 8m

d none of these
Eat, sleep GMAT
Join the discussion
Source: — Problem Solving |

by killer1387 » Fri Mar 23, 2012 11:21 pm
romitvsingh wrote:The curved surface of a cylinder is 264m^2.Its volume is 924m^3. The height of the cylinder must be

a 4m

b 6m

c 8m

d none of these
b 6M
Join the discussion

by rijul007 » Sat Mar 24, 2012 12:00 am
Curved Surface area = 2πrh = 264
πrh =132 = 4*3*11

Volume = πr²h = 924 = 4*3*7*11

πrh*r = 924
r = 7

πrh = 132
3.14*7*h = 132
22h ≈ 132
h ≈ 132/22
h ≈ 6

IMO B
Join the discussion

by Brent@GMATPrepNow » Sun Mar 25, 2012 6:13 am
romitvsingh wrote:The area of curved surface of a cylinder is 264m^2.Its volume is 924m^3. The height of the cylinder must be
a 4m
b 6m
c 8m
d none of these
The area of the curved surface of a cylinder = 2(pi)rh
So, if this area is 264, we can write 2(pi)rh = 264
Divide both sides by 2 to get (pi)rh = 132

The volume of a cylinder = (pi)(r^2)h
So, if the volume is 924, we can write (pi)(r^2)h = 924

From here, we can "divide" the equations to get:
(pi)(r^2)h/(pi)rh = 924/132
Simplify to get: r=7

Now that we know the value of r, we can plug this value into either equation to find the value of h.

How about: (pi)(7)h = 132
This means that h = 132/7pi
As you can see, h cannot be an integer, so the answer must be D.

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion

by romitvsingh » Tue Mar 27, 2012 10:59 am
Brent@GMATPrepNow wrote:
romitvsingh wrote:The area of curved surface of a cylinder is 264m^2.Its volume is 924m^3. The height of the cylinder must be
a 4m
b 6m
c 8m
d none of these
The area of the curved surface of a cylinder = 2(pi)rh
So, if this area is 264, we can write 2(pi)rh = 264
Divide both sides by 2 to get (pi)rh = 132

The volume of a cylinder = (pi)(r^2)h
So, if the volume is 924, we can write (pi)(r^2)h = 924

From here, we can "divide" the equations to get:
(pi)(r^2)h/(pi)rh = 924/132
Simplify to get: r=7

Now that we know the value of r, we can plug this value into either equation to find the value of h.

How about: (pi)(7)h = 132
This means that h = 132/7pi
As you can see, h cannot be an integer, so the answer must be D.

Cheers,
Brent
your ans is wrong its b) 6
Eat, sleep GMAT
Join the discussion

by Brent@GMATPrepNow » Tue Mar 27, 2012 11:18 am
romitvsingh wrote: your ans is wrong its b) 6
The height of the cylinder is 132/(7pi). This does not equal 6.
Sure, it's close to 6 (6.002414997etc), but it does not equal 6.

On the GMAT, the wording in the original question would never allow for 132/(7pi) to equal 6.

If we were to rewrite the original question to fit GMAT's sense of mathematical correctness, it would look something like this:

The area of the curved surface of a cylinder is 264, and its volume is 924. Which of the following is the best approximation of its height?
A) 4
B) 6
C) 8
D) 10
E) 12

Here, the word "approximation" allows for some wiggle room regarding the accuracy of the solution, the removal of the answer choice "none of these" eliminates ambiguity, and 5 answer choices (instead of 4) fits the GMAT standard.

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion

by ronnie1985 » Wed Mar 28, 2012 10:36 am
simple calculations yield the result of 12 m
Follow your passion, Success as perceived by others shall follow you
Join the discussion