Mean & Median

1) let Q=(200,202,204) and P=(1,3,5)
=>mean of Q(202)>mean of P(3) (for evenly spaced integers mean=median)

if Q=(2,4,6) and P=(101, 103,105)
mean of Q(4)<mean of P(103)
not suff


2) median of set Q is higher than the mean of set P
=>mean of Q>mean of P (for evenly spaced integers mean=median)
sufficent

hence B

2) median of set Q is higher than the mean of set P
=>mean of Q>mean of P (for evenly spaced integers mean=median)
sufficent

hence B

you're using info from statement 1) in the analysis of statement 2)

Answer is C)

avenus wrote:

2) median of set Q is higher than the mean of set P
=>mean of Q>mean of P (for evenly spaced integers mean=median)
sufficent

hence B

you're using info from statement 1) in the analysis of statement 2)

Answer is C)

You are correct, answer should be C.

Vemuri wrote:If 2 sets of numbers P & Q have the same number of elements, is the mean of set Q lower than the mean of set P?

1. Set Q consists of consecutive even integers and set P consists of consecutive odd integers.

2. The median of set Q is higher than the mean of set P.

1. Insufficient ie, Q 2,4,6, P 1,3,5 or Q 2,4,6, P 5,7,9
2. Insufficient ie, Q 12,14,16, P 1,13,101

Together Q>P so C)

thanks so much for pointing out Avenus. I need to watch out. i keep getting tricked in ds..