Is C the answer??
Pls let me know the OA.
thanks
-V
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vittalgmat
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statement 1
int 4 is closest to x+y
3.5<=x+y<4.5
Not sufficient since no way to determine even a rough x
statement 2
.5<=x-y<1.5
same as previous
Not sufficient
statement 1/2 together
You are tempted to say:
x+y=4
x-y=1
-------
2y=3
y=3/2 and then x= 5/2 which x would be closest to 3
HOWEVER the actual equation would be:
3.5<=x+y<4.5
.5<=x-y<1.5
I would say E.
int 4 is closest to x+y
3.5<=x+y<4.5
Not sufficient since no way to determine even a rough x
statement 2
.5<=x-y<1.5
same as previous
Not sufficient
statement 1/2 together
You are tempted to say:
x+y=4
x-y=1
-------
2y=3
y=3/2 and then x= 5/2 which x would be closest to 3
HOWEVER the actual equation would be:
3.5<=x+y<4.5
.5<=x-y<1.5
I would say E.
