Please help me solve this q ---------------------------------------------------------------------------- Q1) If (x + 2)^2 = 9 and (y + 3)^2 = 25, then the maximum value of x / y is 1) 1 / 2 2) 5 / 2 3) 5 / 8 4) 1 / 8 5) None Guys, I am sorry but I do not know what the correct answer is i tried this way , i divided the x expression with y expression and ended up with (x+2)/(y+3) = 3/5 . Stuck. Is the approach right ? If yes then how do i proceed ? Thanks Amit

amitdgr wrote:Please help me solve this q ---------------------------------------------------------------------------- Q1) If (x + 2)^2 = 9 and (y + 3)^2 = 25, then the maximum value of x / y is 1) 1 / 2 2) 5 / 2 3) 5 / 8 4) 1 / 8 5) None Guys, I am sorry but I do not know what the correct answer is :? i tried this way , i divided the x expression with y expression and ended up with (x+2)/(y+3) = 3/5 . Stuck. Is the approach right ? If yes then how do i proceed :( ? Thanks Amit I think this is a simple "Plug-and-Chug" First you have to solve for X. (x+2)^2 = 9 We also know that (plus or minus 3)^2 = 9 So X must equal (1) or (-5) Because (1+2)=3 and (-5+2)=-3 We know the values for X, now lets move on to Y (y + 3)^2 = 25 Just like before, we know that (plus or minus 5)^2 = 25 So Y must equal (2) or (-8) Because (2+3)=5 and (-8+3)=-5 As for the maximum value, you can try combinations of the numbers (x/y) to find the highest value. In this case it is (-5)/(-8) and the negatives cancel out to (5)/(8)