BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
Live EA class + 6 months of EA OnDemand
  • Expert-led weekly online sessions
  • EA Masterclass access between classes
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

130-point score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Math problem doubt - Hexagon

Expert replies
by getk » Sun Oct 05, 2008 11:57 am
Three segments drawn between opposite vertices of a Hexagon are of the same length. I was thinking, then it should be regular hexagon.
Can you please explain if it can be any other type of hexagon? (i meant a non-regular one)
Join the discussion
Source: — Problem Solving |

by stop@800 » Sun Oct 05, 2008 9:15 pm
IMO NO

For regular figures
All angles has to be equal.
which we can easily violate in situation described by you.

Whats the answer you have?
Join the discussion

by getk » Mon Oct 06, 2008 3:07 am
i found this in 800score
They are saying that,
condition of all 3 diagonals being equal doesn't mean the hexagon is a regular hexagon..
Join the discussion

by mental » Mon Oct 06, 2008 4:42 am
AGREED WITH STOP
it need not be a reg hexagon

just draw three lines intersecting each other, ensuring that the angle between them is not same

simpler, draw three lines with different intersecting points.
Join the discussion

by getk » Mon Oct 06, 2008 12:15 pm
thanks mate.. that's easy to imagine..
Join the discussion

by artistocrat » Mon Oct 06, 2008 9:00 pm
easier still imagine a chain with six links of equal length. of course you can elongate the ring ;-)
Join the discussion

by Vemuri » Wed Apr 29, 2009 8:40 am
stop@800 wrote:IMO NO

For regular figures
All angles has to be equal.
which we can easily violate in situation described by you.

Whats the answer you have?
I agree that when all angles are equal, the hexagon can be called a regular hexagon. But, when the 3 diagonals drawn between opposite vertices of a hexagon are of equal length, won't the angles also automatically be equal? I am not able to contradict it. Can someone help explain this better?
Join the discussion

by dumb.doofus » Wed Apr 29, 2009 1:27 pm
Vemuri wrote:
stop@800 wrote:IMO NO

For regular figures
All angles has to be equal.
which we can easily violate in situation described by you.

Whats the answer you have?
I agree that when all angles are equal, the hexagon can be called a regular hexagon. But, when the 3 diagonals drawn between opposite vertices of a hexagon are of equal length, won't the angles also automatically be equal? I am not able to contradict it. Can someone help explain this better?
Food for thought: Two isosceles triangle having the two sides of equal lengths can have different angles. That's the same logic you need to apply here.. three diagonals can be of equal length but that doesnt mean that internal angles of the hexagon would all be 120 degrees. It all depends upon the angle of intersection of the diagonals..

HTH[/b]
One love, one blood, one life. You got to do what you should.
https://dreambigdreamhigh.blocked/
https://gmattoughies.blocked/
Join the discussion