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math letter counting PS

Expert replies
by Castor.kim » Tue Nov 13, 2012 1:19 am
It's a problem from GMAT institute.

A code consists of three of the 26 letters. The first and third letters are different consonants and the second letter is a vowel. How many such codes are possible?

it's PS problem, but not an official, so it has no option :)
the answer is 2100

but I don't know how to get this answer..
please someone help me..
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Source: — Problem Solving |

by Brent@GMATPrepNow » Tue Nov 13, 2012 6:18 am
Castor.kim wrote: A code consists of three of the 26 letters. The first and third letters are different consonants and the second letter is a vowel. How many such codes are possible?
Take the task of creating the code and break it into stages.

Stage 1: Select the first letter
Since this letter must be a consonant, and since there are 21 consonants, this stage can be completed in (21 ways).

Stage 2: Select the second letter
Since this letter must be a vowel, and since there are 5 vowels (a, e, i, o, u), this stage can be completed in (5 ways).

Stage 3: Select the third letter
Since this letter must be a consonant, and since we already used 1 consonant for the first letter, there are now 20 consonants remaining.
So, this stage can be completed in (20 ways).

By the Fundamental Counting Principle (FCP) we can complete all 3 stages (and thus create a 3-letter code) in (21)(5)(20) ways ([spoiler]= 2100 ways[/spoiler])

Aside: For more information about the FCP, we have a free video on the subject: https://www.gmatprepnow.com/module/gmat-counting?id=775

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by Castor.kim » Wed Nov 14, 2012 12:37 am
Thanks a lot Brent, after seeing your solution.. it looks simple and easy :)

I had solve it using..
21C2 * 5C1 * 2!(first and third letters change)..

I know.. looks stupid.. :)
Thanks again Brent!!
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