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math_5

Expert replies
Source: — Problem Solving |

by sankruth » Fri Jan 18, 2008 1:23 am
x^2 is less than 1/x in all 3 options, so x < 1.

if x = 0.1

x^2 = 0.01, 2x = 0.2, 1/x = 10 (I)

If x = 0.9
x^2 = 0.81, 1/x = 10/9 (~1) 2x = 1.8 (II)

Option D (I & II only)
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by II » Fri Jan 18, 2008 3:47 pm
agree with Sankruth.

I suppose the trap here is if you plug in simple values (for when x<1) such as x=1/2 for example.
so you could assume that x²<2x<1/x is true for all values of x, where x<1.

But for 9/10 or 0.9 this doesnt hold true !

Sankruth ... what made you pick 0.9 as a value to plug-in here ?

Thanks.
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