Mary made a trial mix that consists of 30 peanuts, 40 raisins, 10 chocolate candies, and 20 banana chips...

BTGmoderatorLU wrote: ↑

Tue Apr 21, 2020 2:37 pm

Source: Princeton Review

Mary made a trial mix that consists of 30 peanuts, 40 raisins, 10 chocolate candies, and 20 banana chips. She picks one item from the bag at random. What is the probability that she picks either a chocolate candy or a banana chip?

A. 1/50
B. 1/10
C. 1/5
D. 3/10
E. 7/10

The OA is D

Total no. of items = 30 + 40 + 10 + 20 = 100

Total no. of chocolate candies and banana chips = 10 + 20 = 30

Required probability = 30/100 = 3/10

The correct answer: D

Hope this helps!

-Jay
_________________
Manhattan Review Test Prep

Locations: Manhattan Review Bangalore | Free GRE Practice Test | GRE Prep Hyderabad | Kukatpally GRE Coaching | and many more...

Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.

BTGmoderatorLU wrote: ↑

Tue Apr 21, 2020 2:37 pm

Source: Princeton Review

Mary made a trial mix that consists of 30 peanuts, 40 raisins, 10 chocolate candies, and 20 banana chips. She picks one item from the bag at random. What is the probability that she picks either a chocolate candy or a banana chip?

A. 1/50
B. 1/10
C. 1/5
D. 3/10
E. 7/10

The OA is D

There are 100 items in the bag, including 10 chocolate candies and 20 banana chips. We add the probabilities of the individual items to obtain the probability of picking either a chocolate candy (C) or a banana chip (B).

P(C or B) = 10/100 + 20/100 = 30/100 = 3/10

Answer: D