A 10-by-6 inch piece of paper is used to form the lateral surface of a cylinder. If the entire piece of paper is used to make the lateral surface, which of the following must be true of the two possible cylinders that can be formed?
A)The volume of the cylinder with height 10 is 60 /Pie cubic inches greater than the volume of the cylinder with height 6.
B)The volume of the cylinder with height 6 is 60 / Pie cubic inches greater than the volume of the cylinder with height 10.
C)The volume of the cylinder with height 10 is 60PIE cubic inches greater than the volume of the cylinder with height 6.
D) The volume of the cylinder with height 6 is 60 Pie cubic inches greater than the volume of the cylinder with height 10.
E) The volume of the cylinder with height 6 is 240 /Pie cubic inches greater than the volume of the cylinder with height 10.
Can someone explain why this isn't D?
Here is how I did it
V1=Pie*(R^2)*H
V2= Pie*(R^2)*H
For V1 R=3 H=10 V1= 90Pie
for V2 R=5 H= 6 V2= 150pie
Thus H=6 is 60pie greater than H=10? Why is it 60/Pie instead of 60pie
A)The volume of the cylinder with height 10 is 60 /Pie cubic inches greater than the volume of the cylinder with height 6.
B)The volume of the cylinder with height 6 is 60 / Pie cubic inches greater than the volume of the cylinder with height 10.
C)The volume of the cylinder with height 10 is 60PIE cubic inches greater than the volume of the cylinder with height 6.
D) The volume of the cylinder with height 6 is 60 Pie cubic inches greater than the volume of the cylinder with height 10.
E) The volume of the cylinder with height 6 is 240 /Pie cubic inches greater than the volume of the cylinder with height 10.
Can someone explain why this isn't D?
Here is how I did it
V1=Pie*(R^2)*H
V2= Pie*(R^2)*H
For V1 R=3 H=10 V1= 90Pie
for V2 R=5 H= 6 V2= 150pie
Thus H=6 is 60pie greater than H=10? Why is it 60/Pie instead of 60pie
