If BD = CD, what is the degree measure of x + y?
(1) v = 74 degrees
(2) w = 32 degrees
Also plz let me know how z+u = 180 here.
(1) v = 74 degrees
(2) w = 32 degrees
Also plz let me know how z+u = 180 here.
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BCD is an isosceles triangle as BD=CD given.
Hence u =v.
ABC is a straight line. So z + v = 180 => z + u = 180. (As u = v)
To find x + y:Also plz let me know how z+u = 180 here.
x + y = 180-z ( In Triangle ABD)
x + y = 180 - (180-v) = v
v needs to be determined to find x + y.
Given the angle of v in (1), (1) is sufficient to determine x + y.
Consider (2): w = 32.
In Triangle BCD, w + u + v = 180 => w + 2v = 180
2v = 180 - w = 180 - 32
=> 2v = 148.
=> v = 74.
v is determined and So is x+y.
(2) is sufficient to determine x + y.
Hence The answer is D.
