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by resilient » Sun Mar 02, 2008 1:29 pm
root (1/36) + (1/64) =?

a.1/12
b.1/7
c.1/10
d.5/24
e.7/24

qa is d
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by smushkas » Sun Mar 02, 2008 2:45 pm
Hey there,

Is it both fractions under sqrt or one? If both of them then it is basic addition and taking out from the sqrt.

For a while forget sqrt and concentarte only on addition. ===> (1/36) + (1/64) = (64 + 36) / ( 36*64 ) = 100 / 2304
fraction 100 / 2304 Num & Den can be divided by 4 and we'll have 100 / 2304 = 25 / 576

which is ==> sqrt[(1/36) + (1/64)] = sqrt[(25 / 576)] = (5 / 24)

Hope it is clear!
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by xilef » Mon Mar 03, 2008 3:55 pm
Same solution with slightly smaller numbers:

sqrt (1/36 + 1/64) = sqrt [ 1/4 * (1/9 + 1/16) ] = 1/2 * sqrt (25/144) = 5/24
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aha

by resilient » Mon Mar 03, 2008 10:49 pm
I saw my mistake thanks to you guys. I added the fractions wrong bynot seeing the reason for the 100 in numerator. Tricky but doable? thanks folks
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