Management

5 odd positions & 5 even positions

6 non-vowel letters - M,M,G,T,N,N
4 vowel letters = A,A,E,E

5 even places can be arranged in 5! ways and other 5 odd places can be arranged in 5! ways. But in this case 1 consonant has to be on EVEN position and for this there are 6 options as any one of the consonants can be there.

So no. of ways = 5!*5!*6 = 86400

Now there are repetitions of 2M,2N,2A,2E

So divide by 2*2*2*2
Total no of ways = 86400/16 =5400

When did N become a vowel?

N is not a vowel. In fact, if it were, the answer would be zero because there would be 6 vowels and only 5 even positions.

Tani,
Can we plz have your solution to the question.

Thanks

hey the answer by vikram is right,if I am not wrong.
I think that's the OA, isn't'it?

Sry guys, changed my solution above to correct the typo.