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List K consists of 12 consecutive integers. If -4 is the least

Expert replies
by BTGModeratorVI » Wed Apr 22, 2020 11:14 am

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List K consists of 12 consecutive integers. If -4 is the least integer in list K, what is the range of the positive integers in list K?

A. 5
B. 6
C. 7
D. 11
E. 12

Answer: B
Source: GMATPrep practice test
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Source: — Problem Solving |

BTGModeratorVI wrote: ↑
Wed Apr 22, 2020 11:14 am
List K consists of 12 consecutive integers. If -4 is the least integer in list K, what is the range of the positive integers in list K?

A. 5
B. 6
C. 7
D. 11
E. 12

Answer: B
Source: GMATPrep practice test
Given that 2 consecutive integers, starting with –4, List K has –4, –3, –2, –1, 0, 1, ,2, 3, 4, 5, 6, and 7.

The range of positive integers = 7 – 1 = 6.

The correct answer: B

Hope this helps!

-Jay
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BTGModeratorVI wrote: ↑
Wed Apr 22, 2020 11:14 am
List K consists of 12 consecutive integers. If -4 is the least integer in list K, what is the range of the positive integers in list K?

A. 5
B. 6
C. 7
D. 11
E. 12

Answer: B
Source: GMATPrep practice test
We are given that list K has 12 consecutive integers and that -4 is the least integer in the set. We need to find the largest integer in the list and we can use the following formula:
largest integer – smallest integer + 1 = quantity of integers in the set
largest integer – (-4) + 1 = 12
largest integer + 4 + 1 = 12
largest integer + 5 = 12
largest integer = 7
Thus, the positive integers in the set are 1, 2, 3, 4, 5, 6, and 7, so the range is 7 – 1 = 6.
Answer: B

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