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Linear problem

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Source: — Problem Solving |
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by clock60 » Sat May 15, 2010 1:01 pm
dkumar.83 wrote:Image
one possible way to solve is to adopt the problem to smth old one
say scale S=axis x and x1=30, x2=60 (on x-y plane)
R scale =axis y y1=6, and y2=24
find the slope=(y2-y1)/(x2-x1)=(24-6)/(60-30)=3/5
function is linea 3/5=(y-24)/(100-60)=48, where y corresponds to the measurement on R scale
i got 48-C
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by gmatmachoman » Sat May 15, 2010 1:08 pm
Linear equation is of the form

y= m*x + C

Let Y belong to R scale & X belong to S scale

6= m*30 +C ----eq 1

24= m*60 +C ----eq 2

solve for m & C

we get m=3/5 & c= -12

Substitute these values in the "required " eqn as:

R scale : m* S +C
: 3/5 *100 +(-12)
:60-12
:48

Solved!!
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by Stuart@KaplanGMAT » Sat May 15, 2010 7:13 pm
Hi!

Here's an explanation from an older post (a search of "r scale" found the old thread).

https://www.beatthegmat.com/pls-help-t12930.html
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