Line Intersection

Whenever you post inequalities, make sure you click the "disable HMTL in this post" box below the text window. HTML uses < and > for tags and if you have HTML on your inequalities will get all squishy!

Similarly, if you ever see a smiley in one of your posts and didn't mean to put one there, it's probably because you typed 8) and didn't disable Smilies.

Interesting question!

If there is at all an intersection, it would be a single point (obvious)

In that case

=> aX - b = X2 + b

=> X2 – aX + 2b = 0


For a real solution of X,

i.è. B2 – 4AC > 0



i.e. (-a)2 – 4 * 2b >0

i.e. b < a2/8



Irrespective of any sign of a, if b is less than zero, that would do the needful, therefore B should be the right answer.


Regards,
Mayank

mayank,

let go parabola but whenever a single degree equation cuts an n degree equation there will be a n point cut.

since I cannot see the options, I don't know the final response but here is a way to solve it:

x^2 + B = Ax - B
<=> x^2 - Ax + 2B = 0 <=>
<=> x=[A +- sqrt(A^2 - 8B)]/2

therefore we have to analyse de root:
if A^2 - 8B < 0 - No intersection
if A^2 - 8B = 0 - One intersection
if A^2 - 8B > 0 - two intersections

To anwser the question we need to know if there is at least one inters, i.e., A^2 - 8B >=0,

Thus,
[A >= sqrt(8B) or A < -sqrt(8B) ] and b>0

Now we can only anwser depending on the info given..