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Let \(M\) be the maximum value and \(N\) be the minimum value of the expression \(\dfrac{x^2+y}{y}\) if \(a\le x\le b\)

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by VJesus12 » Sun Apr 25, 2021 1:24 pm

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Let \(M\) be the maximum value and \(N\) be the minimum value of the expression \(\dfrac{x^2+y}{y}\) if \(a\le x\le b\) and \(c\le y\le d,\) then what is the value of \(M - N?\)

(1) \(d = 7\)
(2) \(a = -2, b = 5\) and \(c = 3\)

Answer: B

Source: Princeton Review
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Source: — Data Sufficiency |