If x, y, and z are positive integers and 3x = 4y = 7z, then the least possible value of x + y + z is
(A) 33
(B) 40
(C) 49
(D) 61
(E) 84
Q/A-d
(A) 33
(B) 40
(C) 49
(D) 61
(E) 84
Q/A-d
Hi Ankitaverma,Ankitaverma wrote:If x, y, and z are positive integers and 3x = 4y = 7z, then the least possible value of x + y + z is
(A) 33
(B) 40
(C) 49
(D) 61
(E) 84
Q/A-d
Given : 3x = 4y = 7z
To find the least value of X+Y+Z ?
X= 7*4 =28
Y= 3*7 =21
Z= 3*4 =12
X+Y+Z =61
Answer is D
Regards,
Uva.
