BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
Vote for Target Test Prep, Newsweek Readers’ Choice Awards 2026
NEWSWEEK READERS’ CHOICE 2026

BIG NEWS! Target Test Prep has been nominated, and they’d love your vote!

TTP has worked incredibly hard to build the best test prep experience possible, and winning Newsweek’s 2026 Readers’ Choice Award for Best Test Prep would mean a lot to them. If TTP has helped you, they’d be incredibly grateful for your vote. You can vote once each day through September 9.

Vote for TTP
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Largest possible number that could be divided into x and 2,1

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
User avatar
Senior | Next Rank: 100 Posts
Posts: 94
Joined: Sun Aug 29, 2010 3:40 amFollowed by: 1 member
Thanked: 3 times
by leonswati » Sun Sep 18, 2011 6:07 pm
Three is the largest number that can be divided evenly into 27 and the positive integer x, while 10 is the largest number that can be divided evenly into both 100 and x. Which of the following is the largest possible number that could be divided into x and 2,100?
30
70
210
300
700

I have no Idea how to approach this... Need help....

Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Senior | Next Rank: 100 Posts
Posts: 33
Joined: Mon Feb 15, 2010 3:40 pm

by Juggernaut_86 » Sun Sep 18, 2011 7:30 pm
Hi,

Is the answer C - 210?

Thanks!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 504
Joined: Tue Apr 19, 2011 1:40 pmFollowed by: 11 members
Thanked: 114 times

by knight247 » Sun Sep 18, 2011 11:25 pm
Hi,

This is a GCD Problem. You may want to brush up on ur GCD and LCM finding skills as this explanation would require it.

If we prime factorise 27 and x we have
27=3^2
x=unknown
GCD=3
Meaning x has a MAXIMUM of one 3 in its prime factorisation. Not more.

Similarly,
100=2^2*5^2
x=3*unknown
GCD=2*5
Meaning x has a MAXIMUM of one 2 and one 5 in its prime factorisation. Not more.

So combining both we have x=2*3*5*unknown
We now have to find the GCD of 2100 and x

2100=(2^2)*(3)*(5^2)*(7)
x=2*3*5*unknown
GCD=2*3*5=30

Hence A
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Newbie | Next Rank: 10 Posts
Posts: 2
Joined: Mon Sep 19, 2011 12:30 am

by excavator » Mon Sep 19, 2011 1:01 am
Hi,

I agree with knight247

I would suggest another method for the same.
Since x is evenly divisible by 3 and 10.
Hence the largest value for x would be 30
Now the GCD..i.e the largest divisor of both for 1200 and 30 would be 30
So its A
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Senior | Next Rank: 100 Posts
Posts: 94
Joined: Sun Aug 29, 2010 3:40 amFollowed by: 1 member
Thanked: 3 times

by leonswati » Mon Sep 19, 2011 5:33 am
Hey Knight,

The IMO to this is c that is 210.... Can u think of as to why is it 210....? thanks...
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Senior | Next Rank: 100 Posts
Posts: 94
Joined: Sun Aug 29, 2010 3:40 amFollowed by: 1 member
Thanked: 3 times

by leonswati » Mon Sep 19, 2011 5:35 am
Juggernaut_86...

can u plz explain how did u get 210
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 504
Joined: Tue Apr 19, 2011 1:40 pmFollowed by: 11 members
Thanked: 114 times

by knight247 » Mon Sep 19, 2011 5:52 am
Yes you are right. The OA is C

Check the following link

https://www.beatthegmat.com/number-system-t90932.html
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1