BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Kay began a certain game with x chips

Expert replies
by Needgmat » Thu Sep 22, 2016 8:22 am
Kay began a certain game with x chips. On each of the next two plays, she lost one more than half the number of chips she had at the beginning of that play. If she had 5 chips remaining after her two plays, then x is in the interval

A) 7 <equal x <equal 12

B) 13<equal x <equal 18

C) 19<equal x <equal 24

D) 25<equal x <equal 30

E) 31<equal x <equal 35

OAD

Please explain.

Many thanks in advance.

Kavin
Join the discussion
Source: — Problem Solving |

by DavidG@VeritasPrep » Thu Sep 22, 2016 8:40 am
Needgmat wrote:Kay began a certain game with x chips. On each of the next two plays, she lost one more than half the number of chips she had at the beginning of that play. If she had 5 chips remaining after her two plays, then x is in the interval

A) 7 <equal x <equal 12

B) 13<equal x <equal 18

C) 19<equal x <equal 24

D) 25<equal x <equal 30

E) 31<equal x <equal 35

OAD

Please explain.

Many thanks in advance.

Kavin
You could test the answer choices. If she loses one more than 1/2 of the original amount, we know that she must have started with an even number of chips, otherwise, we'd be dealing with non-integer values.

Try C. Pick an even number in the interval. Say x = 22. If she loses one more than 1/2 of her chips, she'll lose 11 + 1 = 12 chips, leaving her with 10 chips. If she has 10 chips to start round 2, and again, she loses one more than 1/2 of her chips, she'll lose 5 + 1 = 6 chips, leaving her with 4. But we know she has 5. (Notice that if you were to test another value in this interval and set x = 24, you'd end up with a non-integer value after the second round.)

So Try D. Say x = 26. If she loses one more than 1/2 of her chips, she'll lose 13 + 1 = 14 chips, leaving her with 12 chips. If she has 12 chips to start round 2, and again, she loses one more than 1/2 of her chips, she'll lose 6 + 1 = 7 chips, leaving her with 5. And so D is our answer.
Veritas Prep | GMAT Instructor

Veritas Prep Reviews
Save $100 off any live Veritas Prep GMAT Course
Join the discussion

by [email protected] » Thu Sep 22, 2016 8:46 am
Hi Kavin,

This question can be solved by TESTing THE ANSWERS.

The prompt tells us that Kay lost 1 MORE than HALF of her chips each 'play' and ended up with 5 chips after 2 'plays', so the number of starting chips has to be more than 20 (since half of 20 is 10 and half of 10 is 5). In addition, the starting number of chips CANNOT be an odd number, since you would end up with a 'fraction of a chip' at some point, which is not possible.

Let's TEST Answer C. The upper-end of that range is 24...

IF...Kay started with 24 chips....

Half+1 of 24 = 12+1 = 13 which leaves 11 chips
Half+1 of 11 = 5.5 + 1 = 6.5 which leaves 4.5 chips. This is TOO SMALL (it's supposed to be 5 chips).

This example is pretty close to what we're looking for though, so let's try a number just a little bigger...

Answer D.

IF...Kay started with 26 chips....

Half+1 of 26 = 13+1 = 14 which leaves 12 chips
Half+1 of 12 = 6 + 1 = 7 which leaves 5 chips. This is an exact MATCH for what we were told, so this MUST be the answer.

Final Answer: D

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
Image
Join the discussion

by DavidG@VeritasPrep » Thu Sep 22, 2016 8:48 am
Needgmat wrote:Kay began a certain game with x chips. On each of the next two plays, she lost one more than half the number of chips she had at the beginning of that play. If she had 5 chips remaining after her two plays, then x is in the interval

A) 7 <equal x <equal 12

B) 13<equal x <equal 18

C) 19<equal x <equal 24

D) 25<equal x <equal 30

E) 31<equal x <equal 35

OAD

Please explain.

Many thanks in advance.

Kavin
And there's always good old-fashioned algebra.

Round 1: If we start with x, and we lose 1 more than 1/2 of those chips, we'll lose (1/2)x + 1 chips, leaving us with x - [(1/2)x + 1] or (1/2)x - 1 chips.

Round 2: If we were to lose 1 more than 1/2 of those chips, we'd lose [(1/2)x - 1]/2 + 1 chips. Simplifying, this expression, we're losing (1/4)x - (1/2) + 1 or (1/4)x + 1/2 chips. Because we started this round with (1/2)x - 1 chips, we'd be left with (1/2)x - 1 - [(1/4)x + 1/2] chips. Simplify to get (1/4)x - 3/2.

So (1/4)x - 3/2 = 5, or (1/4)x = 13/2, and x = 52/2 = 26.
Veritas Prep | GMAT Instructor

Veritas Prep Reviews
Save $100 off any live Veritas Prep GMAT Course
Join the discussion