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Joseph bought two varieties of rice, costing 5 cents per ounce and 6 cents per ounce each, and mixed them in some ratio. Then he sold the mixture at 7 cents per ounce, making a profit of 20 percent. What was the ratio of the mixture?
A. 1:10
B. 1:5
C. 2:7
D. 3:8
E. 5:7
The OA is B.
From 20%, we can obtain the cost price (x) of the mixture before profit,
120/100*x = 7 --> x = 35/6.
From the answers, we need to find an option that satisfies the above cost price of 35/6.
Option A (5+6*10)/11=65/11
Option B (5+6*5)/(6)=35/6.
Hence option B is the correct answer.
Has anyone another strategic approach to solve this PS question? Regards!
A. 1:10
B. 1:5
C. 2:7
D. 3:8
E. 5:7
The OA is B.
From 20%, we can obtain the cost price (x) of the mixture before profit,
120/100*x = 7 --> x = 35/6.
From the answers, we need to find an option that satisfies the above cost price of 35/6.
Option A (5+6*10)/11=65/11
Option B (5+6*5)/(6)=35/6.
Hence option B is the correct answer.
Has anyone another strategic approach to solve this PS question? Regards!
