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John has 12 clients and he wants to use color-coding to identify each client. If either a single color or a pair of two

Expert replies
by Vincen » Thu Jun 24, 2021 10:45 am

Timer

00:00

Answers

A

B

C

D

E

Stats

Difficulty—

John has 12 clients and he wants to use color-coding to identify each client. If either a single color or a pair of two different colors can represent a client code, what is the minimum number of colors needed for the coding? Assume that changing the color order within a pair does not produce different codes.

A. 24
B.12
C. 7
D. 6
E. 5

Answer: E

Source: GMAT Club Tests
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Source: — Problem Solving |

Vincen wrote: ↑
Thu Jun 24, 2021 10:45 am
John has 12 clients and he wants to use color-coding to identify each client. If either a single color or a pair of two different colors can represent a client code, what is the minimum number of colors needed for the coding? Assume that changing the color order within a pair does not produce different codes.

A. 24
B.12
C. 7
D. 6
E. 5

Answer: E

Source: GMAT Club Tests
We need to be able to create AT LEAST 12 codes (to represent the 12 clients).

Let's test the options, starting with the smallest value....answer choice E

So, can we get 12 or more color codes with 5 colors?
Let's see . . .
1-color codes = 5 (since there are 5 colors)
2-color codes = We need to choose 2 colors from 5. This can be accomplished in 5C2 ways (using combinations). 5C2 = 10

So, using 5 colors, the total number of color codes we can create = 5 + 10 = 15
Perfect!

The answer is 5 (E)
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