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Jim and Nancy each provide the same service at a different

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by BTGmoderatorLU » Thu Jan 03, 2019 2:31 pm

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Source: Princeton Review

Jim and Nancy each provide the same service at a different original price. If both Jim and Nancy discount their original price, is Nancy's discount price less than Jim's discount price?

1) Jim's discount price is 20 percent less than his original price and Nancy's discount price is 30 percent less than her original price.
2) Jim's discount price is $10 less than his original price and Nancy's discount price is $12 less than her original price.

The OA is C
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Source: — Data Sufficiency |

by Jay@ManhattanReview » Thu Jan 03, 2019 10:55 pm
BTGmoderatorLU wrote:Source: Princeton Review

Jim and Nancy each provide the same service at a different original price. If both Jim and Nancy discount their original price, is Nancy's discount price less than Jim's discount price?

1) Jim's discount price is 20 percent less than his original price and Nancy's discount price is 30 percent less than her original price.
2) Jim's discount price is $10 less than his original price and Nancy's discount price is $12 less than her original price.

The OA is C
Say the original prices for Jim and Nancy are J and N, respectively.

We have to determine whether Nancy's discount price is less than Jim's discount price.

1) Jim's discount price is 20 percent less than his original price and Nancy's discount price is 30 percent less than her original price.

Jim's discount price = 80% of J = 0.8J and
Nancy's discount price = 70% of N = 0.7N

Can't compare 0.8J and 0.7N. Insufficient.

2) Jim's discount price is $10 less than his original price and Nancy's discount price is $12 less than her original price.

Jim's discount price = J - 10 and
Nancy's discount price N - 12

Can't compare J - 10 and N - 12. Insufficient.

(1) and (2) together

We have,

0.8J = J - 10 => J = $50; and
0.7N = N - 12 => N = $40

With unique values of J and N, we can compare 0.8J and 0.7N. Sufficient.

The correct answer: C

Hope this helps!

-Jay
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