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Jennifer can buy watches at a price of B dollars per watch, which she marks up by a certain percentage...

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by BTGmoderatorLU » Tue Jul 21, 2020 5:21 am

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Difficulty—

Source: Magoosh

Jennifer can buy watches at a price of B dollars per watch, which she marks up by a certain percentage before selling. If she makes a total profit of T by selling N watches, then in terms of B and T and N, what is the percent of the markup from her buy price to her sell price?

A. 100T/(NB)
B. TB/(100N)
C. 100TN/B
D. ((T/N) – B)/(100B)
E. 100(T – NB)/N

The OA is A
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Re: Jennifer can buy watches at a price of B dollars per watch, which she marks up by a certain percentage...

by Scott@TargetTestPrep » Sat Jul 24, 2021 3:41 am
BTGmoderatorLU wrote: ↑
Tue Jul 21, 2020 5:21 am
 Source: Magoosh

Jennifer can buy watches at a price of B dollars per watch, which she marks up by a certain percentage before selling. If she makes a total profit of T by selling N watches, then in terms of B and T and N, what is the percent of the markup from her buy price to her sell price?

A. 100T/(NB)
B. TB/(100N)
C. 100TN/B
D. ((T/N) – B)/(100B)
E. 100(T – NB)/N

The OA is A
Solution:

If we let m be the markup percentage, we can create the equation:

N * [B(1 + m/100) - B] = T

B + mB/100 - B = T/N

mB/100 = T/N

m = T/N * 100/B = 100T/(NB)

Answer: A

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