BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

Jasmine runs in the park every day. She runs at a constant

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Moderator
Posts: 2544
Joined: Sun Oct 15, 2017 1:50 pmFollowed by: 6 members
by BTGmoderatorLU » Wed May 30, 2018 2:54 pm

Timer

00:00

Answers

A

B

C

D

E

Stats

Difficulty—

Image

Jasmine runs in the park every day. She runs at a constant pace around the perimeter of a small flower patch. The patch has the shape of a triangle whose sides are 20, 20, and 10 meters long. Jasmine starts the jog from point A of the triangle and runs in the direction of the arrow in the figure above. She completes her jog 50 seconds later, after running along 16 sides of the patch. At what speed does Jasmine run in meters per second?

A. 4.6
B. 4.8
C. 5.2
D. 5.4
E. 5.6

The OA is D.

To complete 16 sides of the patch, Jasmine has to run 5 times the perimeter of the triangle and cover additional side AB once.
total distance covered = 5∗(20+20+10)+20
= 270 m
time taken = 50 sec

speed = 270/50
= 5.4 m/s.

Please, can anyone explain another way to solve this PS question? Thanks!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Legendary Member
Posts: 2214
Joined: Fri Mar 02, 2018 2:22 pmFollowed by: 5 members

by deloitte247 » Fri Jul 27, 2018 2:05 am
Side 1 = 20 m
Side 2 = 20 m
side 3 = 10 m
Time taken = 50s
She ran through 16 sides
$$Therefore,\ \frac{16}{3}=\ 5\ r\ 1$$
$$Speed\ =\ ??\ \frac{dis\tan ce}{timetaken}$$
Distance = (Perimeter of triangle * 5) + side 1
NOTE ; following Jasmine direction, she moved all the three sides in 5times + 1 attention side which will be side 1 = 16 sides.
Distance = ([20+20+10] *5) + 20
= 250 + 20 = 270m
$$Speed\ =\frac{270m}{50s}$$
$$=\ 54ms^{-1}$$
Correct Answer is Option D.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 2535
Joined: Sun Oct 29, 2017 2:04 pmFollowed by: 6 members

by swerve » Fri Jul 27, 2018 9:44 am
She runs 16 sides of the triangle. 3 sides correspond to 50 meters. Now by running 5 times around the triangular park, she covers 15 sides. For the 16th side we have to add 20 meters stretch to 5* 50 meters stretch she already covered.

Total distance covered = 5* 50 + 1 *20 = 270 meters in 50 seconds.

Therefore her average speed = total distance/ total time = 270 mtrs / 50 sec = 5.4 m/s.

Regards!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
GMAT Instructor
Posts: 1462
Joined: Thu Apr 09, 2015 9:34 amFollowed by: 22 members
Location: New York, NY
Thanked: 39 times

by Jeff@TargetTestPrep » Sat Aug 18, 2018 7:05 pm
BTGmoderatorLU wrote:Image

Jasmine runs in the park every day. She runs at a constant pace around the perimeter of a small flower patch. The patch has the shape of a triangle whose sides are 20, 20, and 10 meters long. Jasmine starts the jog from point A of the triangle and runs in the direction of the arrow in the figure above. She completes her jog 50 seconds later, after running along 16 sides of the patch. At what speed does Jasmine run in meters per second?

A. 4.6
B. 4.8
C. 5.2
D. 5.4
E. 5.6
Since the perimeter of the triangular patch is 20 + 10 + 20 = 50 meters and it has 3 sides, when Jasmine runs along 16 sides of the patch, she has run the perimeter of the patch 5 times and 1 more side, AB, which is 20 meters. Therefore, she has run 5 x 50 + 20 = 270 meters, and her speed is:

270/50 = 27/5 = 5.4 m/s

Answer: D

Jeffrey Miller
Head of GMAT Instruction
[email protected]

Image

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1