Problem Solving

AAPL wrote:Jalal weighs twice as much as Meena. Meena's weight is 60% of Bahar's weight. Dolly weighs 50% of Laila's weight. Laila weighs 19% of Jala's weight. Who among these 5 persons weighs the least?

A. Bahar
B. Dolly
C. Jalal
D. Laila
E. Meena

An alternative approach is to assign weights that meet the given conditions.

Meena's weight is 60% of Bahar's weight
Let's let Bahar's weight = 100 kg
So, Meena's weight = 60 kg

Jalal weighs twice as much as Meena.
Since Meena weight 60 kg (see above) then Jalal's weight = 120 kg

Laila weighs 19% of Jala's weight
Jalal's weight = 120 kg
19% is very close to 20%
20% of 120 kg = 24 kg
So, 19% of 120 kg = a little less than 24 kg
So, Laila weighs a little less than 24 kg

NOTE: At this point, we can see that, Laila is the lightest (so far!)

Dolly weighs 50% of Laila's weight.
So, Dolly weighs LESS THAN Laila.
So, Dolly must weigh the least

Answer: D

Cheers,
Brent

AAPL wrote:Jalal weighs twice as much as Meena. Meena's weight is 60% of Bahar's weight. Dolly weighs 50% of Laila's weight. Laila weighs 19% of Jala's weight. Who among these 5 persons weighs the least?

A. Bahar
B. Dolly
C. Jalal
D. Laila
E. Meena

We can let Meena's weight be 60 lbs. So Jalal's weight is 120 lbs and Bahar's weight is 60/0.6 = 100 lbs. We can round 19% to 20%, so Laila is approximately 0.2 x 120 = 24 lbs and therefore, Dolly is approximately 0.5 x 24 = 12 lbs. Dolly weighs the least.

Answer: B