BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
Live EA class + 6 months of EA OnDemand
  • Expert-led weekly online sessions
  • EA Masterclass access between classes
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

130-point score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Isoceles Triangles

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Senior | Next Rank: 100 Posts
Posts: 48
Joined: Thu Dec 04, 2008 12:27 pm
Thanked: 1 times
by exhilaration » Sat May 30, 2009 11:44 am
Hi,

Is the fastest way to solve this problem by working backwards from each answer choice until you match their perimeter or is there a faster way to solve this?

Thanks.
Attachments
Q1.jpg
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Senior | Next Rank: 100 Posts
Posts: 49
Joined: Tue May 19, 2009 10:48 am
Location: Chicago
Thanked: 1 times
GMAT Score:680

by Katrusya » Sat May 30, 2009 12:30 pm
a is a side of right triangle.
b is a hypotenuse.
b=a*sqr2

Perimeter = 2a+a*sqr2=16+16*sqr2
a = 8*sqr2
b = a*sqr2= 8*sqr2*sqr2=16
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 104
Joined: Thu Mar 19, 2009 8:05 pm
Location: Ohio, US
Thanked: 6 times

by blackarrow » Sat May 30, 2009 1:17 pm
exactly the approach

Isoceles traingle 2 sides= x and x

Third side = x root 2

Thus perimeter = 2x+x root2 = 16+16 root 2. ...

How the equation is solved is by equating 2x=16root2. Thus x=8root2

Hypotenuse = 8root 2*8 root 2= 16
Its better to burn out than to fade away
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 48
Joined: Thu Dec 04, 2008 12:27 pm
Thanked: 1 times

by exhilaration » Sat May 30, 2009 1:20 pm
blackarrow wrote:exactly the approach

Isoceles traingle 2 sides= x and x

Third side = x root 2

Thus perimeter = 2x+x root2 = 16+16 root 2. ...

How the equation is solved is by equating 2x=16root2. Thus x=8root2

Hypotenuse = 8root 2*8 root 2= 16
wicked. thanks.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1