lheiannie07 wrote:Is y = 6 ?
$$\left(1\right)\ y^2\ =\ 36$$
$$\left(2\right)\ y^2\ -\ 7y\ +\ 6\ =\ 0$$
Target question: Is y = 6 ?
Statement 1: y² = 36
If y² = 36, then EITHER
y = 6 OR
y = -6
Since we cannot answer the
target question with certainty, statement 1 is NOT SUFFICIENT
Statement 2: y² - 7y + 6 = 0
Factor the equation to get: (y - 1)(y - 6) = 0
So, EITHER y - 1 = 0 OR y - 6 = 0
So, EITHER
y = 1 OR
y = 6
Since we cannot answer the
target question with certainty, statement 2 is NOT SUFFICIENT
Statements 1 and 2 combined
Statement 1 tells us that EITHER
y = 6 OR
y = -6
Statement 2 tells us that
y = 1 OR
y = 6
Since BOTH statements are TRUE, we can conclude that
y = 6
Since we can answer the
target question with certainty, the combined statements are SUFFICIENT
Answer:
C
Cheers,
Brent $$$$
Brent Hanneson - Creator of GMATPrepNow.com
