For those who have trouble solving this mentally,
Option 1 i.e., for x*y*z<0, consider the following possibilities and the values for x,y and z are simply assumptions
a) for x*y*z<0, either of x,y,z has to be -ve
1) x -ve, y +ve, z +ve , [x,y,z] = [-1,4,3] (z lies b/w x and y)
2) x +ve, y -ve, z +ve , [x,y,z] = [1,-4,3] (z does not lie b/w x and y)
3) x +ve, y +ve, z -ve , [x,y,z] = [1,4,-3] (z does not lie b/w x and y)
OR
b)
4) all three are -ve i.e,. x,y,z<0 , [x,y,z] = [-1,-4,-3] (z lies b/w x and y)
Since the answer oscillates between yes and no (lies and does not lie), this option is not sufficient
Option 2 i.e., for xy<0, consider the following possibilities
c) for x*y<0, either of x,y has to be -ve
i) if x<0,
5) if z>0, [x,y,z] = [-1,4,3] (z lies b/w x and y)
6) if z<0, [x,y,z] = [-1,4,-3] (z does not lie b/w x and y)
ii) if y<0,
7) if z>0, [x,y,z] = [1,-4,3] (z does not lie b/w x and y)
8) if z<0, [x,y,z] = [1,-4,-3] (z lies b/w x and y)
Again here the answer oscillates between yes and no (lies and does not lie), this option is also not sufficient
Considering both would be the subset of previous option again
if x*y<0 and x*y*z<0, z will be always >0
i) either x<0 is same as 5 above which says (z lies b/w x and y)
ii) either y<0 is same as 7 above which says (z does not lie b/w x and y)
Yes and No again. Hence E.
This looks lengthy and complex on the first time, but if you start working it out with pen and paper (or mentally), this should get solved in less than a minute.
Thanks
Krishna.