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nh8404052006
- Senior | Next Rank: 100 Posts
- Posts: 48
- Joined: Wed Aug 27, 2008 9:58 am
From 1:
|x+1| = 2|x-1|
=> x+1 = 2x-2
=> x=3
When using absolute, solve for -ve also
|x+1| = 2|x-1|
=> x+1 = -2x+2
=> x=1/2
INSUFFICIENT
From 2:
|x-3| <> 0
=> x<>3
So, x could be anything other than 3, INSUFFICIENT
Combining, 1 & 2, We know x=1/3 SUFFICIENT
Hence ANSWER = C
