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Is there a way to solve it other than by calculation

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by Neo2000 » Sun Nov 11, 2007 7:24 am
Root4 = 2

Fourth Root of 4 = Fourth Root of (2quare) = Fourth Root of ((Root2)Squared)) = Root2 = 1.414

Now if Fourth Root of 4 itself is Greater than 1 then Cube Root of 4 will also be greater than 1

Which means the entire sum at the very least has to be greater than 4
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by samirpandeyit62 » Sun Nov 11, 2007 9:21 am
rt (4) =2

cube root of 4 > cube root of 1 i. e 1

fourth root of 4 (4^1/4) > 1^1/4 i.e 1

so total should be grater than 4
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by gmatrant » Sun Nov 11, 2007 6:27 pm
Ill have to blame myself for this mistake... thanks samir and Neo, feel I missed an easy one..
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