is r positive?

Statement 1
S > t
S = 2, t = 1 – r would be +ve
S = -3, t = -4, r can be –ve

So insufficient

Statement 2
R / s + t > 1

R = 4, s = 1, t = 1 - result > 1
R = -1, s = -2, t = -1 – result < 1

Therefore, r has to be +ve to be greater than s + t, if R is negative, then statement 2 is false

Hence statement B is sufficient.

Also you cannot cross multiply if you are not sure whether the number being cross multiplied is +ve or –ve

Consider an example, -3 / -2 > 1, now according to you if I cross multiply, then -3 > -2, which is wrong. Because the number is negative the inequality sign should change

i.e. -3 < -2

The 2nd option is

r/s+t >1


does that mean r/(s+t) > 1 or (r/s)+t>1....


Can you correct accordingly..

mehravikas wrote:Statement 1
S > t
S = 2, t = 1 – r would be +ve
S = -3, t = -4, r can be –ve

So insufficient

Statement 2
R / s + t > 1

R = 4, s = 1, t = 1 - result > 1
R = -1, s = -2, t = -1 – result < 1

Therefore, r has to be +ve to be greater than s + t, if R is negative, then statement 2 is false

Hence statement B is sufficient.

Also you cannot cross multiply if you are not sure whether the number being cross multiplied is +ve or –ve

Consider an example, -3 / -2 > 1, now according to you if I cross multiply, then -3 > -2, which is wrong. Because the number is negative the inequality sign should change

i.e. -3 < -2

well I don't think that statement B is sufficient
take t=1
s=-50
r=-1
here r>s+t
r/s +t >1
and r is negative

IMO C

oh wait..I think I got it..so
its r/(s+t) and not r/s + t

statement 1) not SUFF

2)r/(s+t)>1
now uptowngirl you CANNOT write it as r>s+t, because if (s+t)<0, it will become r<s+t

so possibilities are
r>s+t, when (s+t)>0, so r>0
r<(s+t) when (s+t)<0- but this is not possible because it is given in the question that r>s+t
so SUFF

answer B