BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
Vote for Target Test Prep, Newsweek Readers’ Choice Awards 2026
NEWSWEEK READERS’ CHOICE 2026

BIG NEWS! Target Test Prep has been nominated, and they’d love your vote!

TTP has worked incredibly hard to build the best test prep experience possible, and winning Newsweek’s 2026 Readers’ Choice Award for Best Test Prep would mean a lot to them. If TTP has helped you, they’d be incredibly grateful for your vote. You can vote once each day through September 9.

Vote for TTP
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Is most of the land in City A zoned residential?

Expert replies
by jaymw » Tue Dec 21, 2010 10:25 pm
Source: Kaplan

Is most of the land in City A zoned residential?

(1) All land in City A is zoned as either residential or commercial
(2) The proportion of land zoned residential in City A could be tripled

OA after some discussion
Join the discussion
Source: — Data Sufficiency |

by Night reader » Tue Dec 21, 2010 10:39 pm
jaymw wrote:Source: Kaplan

Is most of the land in City A zoned residential?

(1) All land in City A is zoned as either residential or commercial
(2) The proportion of land zoned residential in City A could be tripled

OA after some discussion
I am after choice E

question: call residential R and Commercial C, then is R>C?
st(1) precisely gives that R+C=Total Lands i.e. only R and C in the set are present; we need the relationship between R and C. Not Sufficient.
st(2) precisely gives that R could become 3*R then C must be C-2*R; again missing the relationship between R and C, as it's possible 3*R < or > or = (C-2*R), moreover we don't what are the other parameters in the set (e.g. some D or F...) Not sufficient.

Combining st(1&2) Not sufficient.
Last edited by Night reader on Tue Dec 21, 2010 11:35 pm, edited 1 time in total.
Join the discussion

by Rahul@gurome » Tue Dec 21, 2010 11:19 pm
Solution:
Let the part which is residential be x and let the other part be y.
We need to know whether x > y or not.
Consider first (1) alone.
We just get that y is commercial.
Obviously, it is not sufficient alone because we do not know how much part is residential and how much part is commercial.
Next consider (2) alone.
We only come to know that x can become 3x which will be less than total land area but we do not come to know whether x > y or not.
Next combine both the statements together and check.
On combining we get that total land area is x + y where x is residential and y is commercial.
Now since x can become 3x, we will have that 3x <= x + y.
Or 2x <= y.
Since x and y are positive, we conclude that x < y.
So most of the area is not residential.

The correct answer is (C).
Rahul Lakhani
Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)
Join the discussion

by Night reader » Tue Dec 21, 2010 11:43 pm
I have just made minor edition to my solution which does not change approach. Below I would like to test my solution as Rahul came with C and I find E as the only possible choice.

question: call residential R and Commercial C, then is R>C?
st(1) precisely gives that R+C=Total Lands i.e. only R and C in the set are present; we need the relationship between R and C. Not Sufficient.
st(2) precisely gives that R could become 3*R then C must be C-2*R; again missing the relationship between R and C, as it's possible 3*R < or > or = (C-2*R), moreover we don't what are the other parameters in the set (e.g. some D or F...) Not sufficient.

Combining st(1&2) Not sufficient.


testing for choice C with 2 alternatives:
1) suppose initially R=2 and C=9, then after changed proportion 3*R or 3*2 and C-2*R or 9- (3*2) => new R=6 and new C=5 => R>C because 6>5
2) suppose initially R=2 and C=11, then after changed proportion 3*R or 3*2 and C-2*R or 11- (3*2) => new R=6 and new C=7 => R<C because 6<7

Therefore, we need relationship between R and C to decide if R < or = or > C
Join the discussion

by Rahul@gurome » Tue Dec 21, 2010 11:55 pm
Night reader wrote:I have just made minor edition my solution which does not change approach. Below I would like to test my solution as Rahul came with C and I find E as the only possible choice.

question: call residential R and Commercial C, then is R>C?
st(1) precisely gives that R+C=Total Lands i.e. only R and C in the set are present; we need the relationship between R and C. Not Sufficient.
st(2) precisely gives that R could become 3*R then C must be C-2*R; again missing the relationship between R and C, as it's possible 3*R < or > or = (C-2*R), moreover we don't what are the other parameters in the set (e.g. some D or F...) Not sufficient.

Combining st(1&2) Not sufficient.


testing for choice C with 2 alternatives:
1) suppose initially R=2 and C=9, then after changed proportion 3*R or 3*2 and C-2*R or 9- (3*2) => new R=6 and new C=5 => R>C because 6>5
2) suppose initially R=2 and C=11, then after changed proportion 3*R or 3*2 and C-2*R or 11- (3*2) => new R=6 and new C=7 => R<C because 6<7

Therefore, we need relationship between R and C to decide if R < or = or > C
But we need to know whether original value of R is more than original value of C or not.
In 1) R=2 < C=9 and 2) R = 2 < C = 11.

In both case it is not.
Rahul Lakhani
Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)
Join the discussion

by Night reader » Wed Dec 22, 2010 12:12 am
Thanks Rahul, I would be misled if not for your expertise :)

this holds true for R<C always, choice C
Join the discussion

by jaymw » Wed Dec 22, 2010 1:07 am
OA is indeed C.

Great explanation, Rahul!
Join the discussion

by Woozler » Wed Dec 22, 2010 11:22 am
Even after Rahul's explanation I still don't get it why it's not (B). If land zoned residential could be tripled then it means that only one third or less of all land in city A is currently zoned residential.
Join the discussion

by Rahul@gurome » Wed Dec 22, 2010 6:56 pm
Woozler wrote:Even after Rahul's explanation I still don't get it why it's not (B). If land zoned residential could be tripled then it means that only one third or less of all land in city A is currently zoned residential.
.

Just consider statement (2) alone.
It means that there can be a third type of area apart from residential and commercial.
Suppose initially residential area R is 8, commercial area C is 2 and some other part say X is 36.
Next if R can be tripled, we can have that R is 24, C is 2, and X is 20.
Here originally R > C.
Now suppose R is 5, C is 6, and X is 36.
If R can be tripled, we can have that R is 15, C is 6, and X is 26.
Here originally R < C.
So from (2) alone nothing definite can be said whether R > C or not.
Rahul Lakhani
Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)
Join the discussion