BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

Is M < 0?

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Legendary Member
Posts: 621
Joined: Wed Apr 09, 2008 7:13 pmFollowed by: 4 members
Thanked: 33 times
by vittalgmat » Thu Dec 25, 2008 1:11 pm
Is M < 0 ?

1. -M = |-M|
2. M^2 = 9


[spoiler]OA: C.
The explanation for 1 says M should be -ve or 0.
Though I guessed C !!, I am not perfectly clear with stmt 1.
How can I test it by plugging in values??
Someone pls explain.
thanks[/spoiler]
Source: Gmatclub: m01 q17
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Data Sufficiency |
Legendary Member
Posts: 2467
Joined: Thu Aug 28, 2008 6:14 pmFollowed by: 11 members
Thanked: 331 times

by cramya » Thu Dec 25, 2008 1:15 pm
Stmt I

-M = |-M|

Take any positive value this will not be true

M= 2

-M = -2

|-M| = |-2| = 2

-M <> |-M|

It will be true for only 0 and negative values

M=-2

-M = -(-2) = 2

|-M| = |-(-2)| = |2| = 2

-M = |-M|


I am sure u got smt II insufficiency already

Using stmt II together wiht stmt I u cal eliminate M being 0 or +3 therefore M is negative and < 0.


Hope this helps!
Last edited by cramya on Thu Dec 25, 2008 1:26 pm, edited 1 time in total.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 621
Joined: Wed Apr 09, 2008 7:13 pmFollowed by: 4 members
Thanked: 33 times

by vittalgmat » Thu Dec 25, 2008 1:22 pm
Thanks Cramya. Now it is clear. When I initially looked at the problem, I started questioning "how can the Absolute of number be -ve"!! . Now I am clear.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1