BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Is integer x odd?

Expert replies
by Gmat_mission » Fri Jun 01, 2018 1:08 am

Timer

00:00

Answers

A

B

C

D

E

Stats

Difficulty

Is integer x odd?

(1) 2x + 1 is odd $$\left(2\right)\ \ \frac{x}{2}\ is\ even.$$ [spoiler]OA=B[/spoiler].

Could anyone explain why is B the correct answer to me? Thanks in advance.
Join the discussion
Source: — Data Sufficiency |

by Brent@GMATPrepNow » Fri Jun 01, 2018 5:47 am
Gmat_mission wrote:Is integer x odd?

(1) 2x + 1 is odd $$\left(2\right)\ \ \frac{x}{2}\ is\ even.$$ [spoiler]OA=B[/spoiler].
Target question: Is integer x odd?

Statement 1: 2x + 1 is odd
Since 2x + 1 is ODD for any integer value, this statement doesn't tell us anything.
To understand what I mean, consider these two cases that satisfy statement 1:
Case a: x = 1. Here, 2x + 1 = 2(1) + 1 = 3, which is odd. In this case, x = 1, so the answer to the target question is YES, x IS odd
Case b: x = 2. Here, 2x + 1 = 2(2) + 1 = 5, which is odd. In this case, x = 2, so the answer to the target question is NO, x is NOT odd
Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT

Statement 2: x/2 is even
If x/2 is even, we can write: x/2 = 2k for some integer k.

----ASIDE----------------
That last step applies to ALL even numbers.
For example, we know that 14 is even, because we can write 14 = 2(something), where that something is an integer
Likewise, we know that 16 is even, because we can write 16 = 2(something), where that something is an integer
--------------------------

If x/2 = 2k for some integer k, we can take x/2 = 2k and multiply both sides by 2 to get: x = 4k (where k is an integer)
This means x must be a multiple 4, which means x is DEFINITELY EVEN
So the answer to the target question is NO, x is NOT odd
Since we can answer the target question with certainty, statement 2 is SUFFICIENT

Answer: B

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion

RE:

by deloitte247 » Sat Jun 02, 2018 2:25 pm
Statement 1 = $$2x+1\ is\ odd$$
The statement 1, 2 and 3.
$$if\ x=1;\ 2x+1=2\left(1\right)+1=3$$ x is odd
$$if\ x=2;\ 2x+1=2\left(2\right)+1=5$$ x is not odd (even)
$$if\ x=3;\ 2x+1=2\left(3\right)+1=7$$ x is odd .It doesnt answer the target question
set statement 2= $$\frac{x}{2\ }$$ is even, if you multiply 2 with any number, it will give us an even number . Therefore $$\frac{x}{2\ }=even\ number$$
$$Let\ the\ even\ number\ be\ 2\cdot y=2y$$
$$Therefore,\ \frac{x}{2}=2y$$
$$x=4y$$
$$This\ means\ x\ is\ a\ multiple\ of\ 4\ which\ is\ an\ even\ number$$
Therefore statement 2 is SUFFICIENT answer is Option B
Join the discussion