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Is \(\dfrac{x}{m}\cdot (m^2+n^2+k^2)=xm+yn+zk?\)
(1) \(\dfrac{z}{k}=\dfrac{x}{m}\)
(2) \(\dfrac{x}{m}=\dfrac{y}{n}\)
Answer: C
Source: Official Guide
(1) \(\dfrac{z}{k}=\dfrac{x}{m}\)
(2) \(\dfrac{x}{m}=\dfrac{y}{n}\)
Answer: C
Source: Official Guide
