St.1.) n^2 < n
St.2.) n^3>0
Please tell how to solve this DS problem.
I got B as answer. [/list]
St.2.) n^3>0
Please tell how to solve this DS problem.
I got B as answer. [/list]
Plug in the valueskashishh wrote: Is 0<n<1
St.1.) n^2 < n
St.2.) n^3>0
Statement 1: SUFFICIENT
We will consider 3 cases here
1) Assume n<0
We know that n^2 is always positive
So when n<0 ,n^2 will always be greater than 0.
=> n^2>n But the statement says the opposite . Hence our assumption is wrong.
2)Assume n>1
For every value of n>1, n^2 will be greater than n
=> n^2> n Again our assumption is wrong.
3)Assume 0<n<1
take n = 1/2, then n^2 = 1/4
=> n^2<n. Hence our assumption is correct and we can answer a definite Yes to our question.
Note : n^2< n only when 0<n<1 . So from next time you won't need to take all the cases mentioned above, as they were just for the explanation purpose.
Statement 2:INSUFFICIENT
This statement only tells us that n>0 . Hence we don't know whether 0<n<1 or n>1
The correct answer is A
