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Interesting Set problem - Gmat800

Expert replies
by netigen » Thu May 08, 2008 12:52 pm
This is an interesting Range problem. I am trying to figure out the best approach to solve it
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Source: — Problem Solving |

answer -> a?

by kbm1975 » Thu May 08, 2008 5:34 pm
in case
set X={1,4,5,6}
set Y={-1,4,5,6}

(1) no -> sufficient from set X
(2) no(from set X), yes(from set Y) -> insufficinet

therefore A

Is it right?
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by arorag » Thu May 08, 2008 6:20 pm
Ans should be A. B is not giving anything abt the sign of nos
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by Stuart@KaplanGMAT » Thu May 08, 2008 7:06 pm
Just a quick note:

(1) is not sufficient alone.

The range of {1, 4, 14} is 13. Adding 13 to the set doesn't increase the range.

The range of {50, 51, 63} is 13. Adding 13 to the set does increase the range.

We can get both a yes and a no, insufficient.
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by netigen » Thu May 08, 2008 7:40 pm
OA is C
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by netigen » Mon May 12, 2008 2:35 pm
This is the solution I found for this Q

1. A is insufficient for the reason noted by Stuart above
2. Lets look at option 2

Avg of set A(n) = Total of Set A(n) / n (assuming n=numbers in set A)

Avg of set A(n+1) = Total of Set A(n) + R/ (n+1) < R

Total of Set A(n) + R < R (n+1)

Total of Set A(n) + R < Rn + R

or Total of Set A(n) / n < R

which means that Avg of set A(n) < R

This means that there are number less than and greater than R in the A hence the range will not increase by addition of R hence the ans C
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by ricaototti » Tue Sep 02, 2008 9:54 pm
I am sorry but I really dont get it why it should be C.
I think it should be E.
I understand why 1 and 2 are wrong... but not why C is correct. Please, can someone explain it better.

Thanks
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by Nycgrl » Tue Sep 02, 2008 10:02 pm
It should be E...what's OA?
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by 4meonly » Wed Sep 03, 2008 10:38 am
E agree
Waiting for OA
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Re: Interesting Set problem - Gmat800

by parallel_chase » Wed Sep 03, 2008 3:37 pm
netigen wrote:This is an interesting Range problem. I am trying to figure out the best approach to solve it
Clearly statement I and II alone are insufficient for the same reasons mentioned by Stuart.

Combining I & II

New number added = R

all the number in the set are positive
NEW MEAN of the set with NEW NUMBER added is less than R.

4,4,4
range = 0
mean = 4

new number= 0
0,4,4,4
mean=3
range=4

Range increased from 0 to 4

2,4,8
range=6

new number=6
2,4,6,8
mean=5
range=6

range remains the same.

Hence E.

I dont know how OA can be C, or am i missing something.
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by Ian Stewart » Wed Sep 03, 2008 3:54 pm
The range of a set A is R. A number having a value of R is added to set A. Will the range of set A increase?
1) All numbers in set A are positive.
2) The mean of the new set is smaller than R.


I think the above posts confirm that the answer is either C or E, so I won't bother looking at the statements individually. Let's look at both statements together.

When we add R to set A, the range will only increase if R is either the largest element in the new set, or the smallest element in the new set. We want to know if R could be the largest or the smallest element in the new set.

Let's assume A contains at least two elements, and call the largest g, and the smallest s. So set A is {s, other stuff, g}. Then R = g - s. From this, because g and s are positive, R must be less than g. So R can't be the largest element in the new set.

The only question is whether R might be the smallest; that is, we want to know if it's possible that R < s. This would make R smaller than everything else in the set, since s was the smallest element of the old set. But if R is the smallest element of the new set, there's no way statement 2 could be true; the mean of a set cannot be smaller than its smallest element. So R can neither be the smallest nor the largest element in the set, and the range of the new set must be equal to the range of the old set. Sufficient. C.
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Re: Interesting Set problem - Gmat800

by Ian Stewart » Wed Sep 03, 2008 3:59 pm
parallel_chase wrote:
New number added = R

all the number in the set are positive
NEW MEAN of the set with NEW NUMBER added is less than R.

4,4,4
range = 0
mean = 4

new number= 0
0,4,4,4
mean=3
range=4
You can't use this example; the mean of the new set is not less than R, the range of the first set, which is zero. This set thus doesn't conform with the information in Statement 2.
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