BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course
Redeem
Featured Course
Target Test Prep GMAT OnDemand
Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.
- 715+ score guarantee — highest in the industry (99th percentile)
- 52 chapters · 1,500+ lessons · 4,000+ practice questions
- 400 hours of video · 1,500+ instructor-led HD smartboard lessons
- 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
- 24/7 live support + weekly Zoom office hours with GMAT instructors
- TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
- 1,200+ flashcards + AI-powered study assistant & daily calendar
- OnDemand, LiveTeach & GMAT Bootcamp formats available
- Also: GRE, SAT Math & Executive Assessment courses
- MBA Admissions Consulting now available
- 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
- 200,000+ students served
- 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★
5.0
(559 reviews)
130-pt guarantee
$0 to start
then $127/mo
Interesting DS question
-
prateek_guy2004
- Master | Next Rank: 500 Posts
- Posts: 398
- Location: India
- Thanked: 41 times
Without even solving it one should understand that in 1 st equation its +2 which is a divisible of 4 and second statement too is a div of 4. so answer is D.
I think the answer is A. because it says x >0
and using the 1st option -> x=4y+4, we have to make sure we put such a value y that makes x >0. So if we put y = -1 then x = -4+4 = 0 so y=-1 is an invalid choice.
Let us try with y = 0, then x = 4 -- divisible by 4. and as in this equation we are adding it with an even number and multiplying by 4 so the result will always be even. Putting x=4 in the main equation
-> 64-48+8 = 24, divisible by 4.
Option 2 - The same rule applies here. We can not assume z to be -1, that will make x as 0. so let us try with 0. that will give us x = 2 and putting it in the main equation - 8-12+4 =0 which is not divisible by 4. So the answer should be A.
Thanks.
Anshul
and using the 1st option -> x=4y+4, we have to make sure we put such a value y that makes x >0. So if we put y = -1 then x = -4+4 = 0 so y=-1 is an invalid choice.
Let us try with y = 0, then x = 4 -- divisible by 4. and as in this equation we are adding it with an even number and multiplying by 4 so the result will always be even. Putting x=4 in the main equation
-> 64-48+8 = 24, divisible by 4.
Option 2 - The same rule applies here. We can not assume z to be -1, that will make x as 0. so let us try with 0. that will give us x = 2 and putting it in the main equation - 8-12+4 =0 which is not divisible by 4. So the answer should be A.
Thanks.
Anshul
I agree... even though the OA is apparently D, can anyone find fault with anshul's explanation of the problem?
The Fault with Anshul Explanantion is :
Stacey Comment :
FYI: the term divisible, or evenly divisible, means that there is no remainder when solving. Zero divided by anything but zero equals zero. No remainder - so zero is, in fact, divisible by 4 (or anything except zero). Zero divided by zero is undefined.
Stacey Comment :
FYI: the term divisible, or evenly divisible, means that there is no remainder when solving. Zero divided by anything but zero equals zero. No remainder - so zero is, in fact, divisible by 4 (or anything except zero). Zero divided by zero is undefined.
Its much easier if we factorise the initial expression to x(x-1)(x-2)
A.) Now when x = 4y + 4 , the expression is divisible by 4 as x is divisible by 4.
B.) Now when x = 2z + 2, then the expression is (2z+2)(2z+1)2z
Again this is equal to 4(z+1)(2z+1)(z), which is divisible by 4.
Hence D is the answer.
A.) Now when x = 4y + 4 , the expression is divisible by 4 as x is divisible by 4.
B.) Now when x = 2z + 2, then the expression is (2z+2)(2z+1)2z
Again this is equal to 4(z+1)(2z+1)(z), which is divisible by 4.
Hence D is the answer.
If x > 0, then is x^3 - 3(x^2) + 2x divisible by 4?
1. x = 4y + 4, where y is an integer
2. x = 2z + 2, where z is an integer
---------------
1. x= 4(y+1) implies x is divisible by 4.
x^3 - 3x^2 +2x = x(x^2-3x+2) = 4(y+1)(x^2-3x+2). Statement 1 is sufficient
2. x = 2(z+1)
x^3 - 3x^2 +2x = 2.2.2(z+1)^3 - 3.2.2(z+1)^2 + 2.2(Z+1). Statement 2 is also sufficient
Ans : D
1. x = 4y + 4, where y is an integer
2. x = 2z + 2, where z is an integer
---------------
1. x= 4(y+1) implies x is divisible by 4.
x^3 - 3x^2 +2x = x(x^2-3x+2) = 4(y+1)(x^2-3x+2). Statement 1 is sufficient
2. x = 2(z+1)
x^3 - 3x^2 +2x = 2.2.2(z+1)^3 - 3.2.2(z+1)^2 + 2.2(Z+1). Statement 2 is also sufficient
Ans : D
-
neelgandham
- Community Manager
- Posts: 1060
- Location: Utrecht, The Netherlands
- Thanked: 318 times
0 is divisible by any number except 0 and the result is 0. Not happy with what you see ?codytravers wrote:I agree... even though the OA is apparently D, can anyone find fault with anshul's explanation of the problem?
ok 0/k = 0*(1/k) = 0 * real number = ? 0 !
Anil Gandham
Welcome to BEATtheGMAT | Photography | Getting Started | BTG Community rules | MBA Watch
Check out GMAT Prep Now's online course at https://www.gmatprepnow.com/
Welcome to BEATtheGMAT | Photography | Getting Started | BTG Community rules | MBA Watch
Check out GMAT Prep Now's online course at https://www.gmatprepnow.com/
D it is. Factorize the expression to remove any ambiguity.
You will get (x-2)(x-1)(x)/4
Hence all we need to know is that x is even.
Both statements address the issue.
You will get (x-2)(x-1)(x)/4
Hence all we need to know is that x is even.
Both statements address the issue.
-
[email protected]
- Legendary Member
- Posts: 934
- Location: AAMCHI MUMBAI LOCAL
- Thanked: 63 times
Guyz according to me the answer is D for this DS quesion.
If x>0, then is x^3-3x^2+2x divisible by 4?
1. x=4y+4 where y is an integer
2. x=2z+2; were z is an integer
So the values for y and z should be > 0 and only intergers, when u put in values you get x divisible by 4.
Hence D...
If x>0, then is x^3-3x^2+2x divisible by 4?
1. x=4y+4 where y is an integer
2. x=2z+2; were z is an integer
So the values for y and z should be > 0 and only intergers, when u put in values you get x divisible by 4.
Hence D...
IT IS TIME TO BEAT THE GMAT
LEARNING, APPLICATION AND TIMING IS THE FACT OF GMAT AND LIFE AS WELL... KEEP PLAYING!!!
Whenever you feel that my post really helped you to learn something new, please press on the 'THANK' button.
LEARNING, APPLICATION AND TIMING IS THE FACT OF GMAT AND LIFE AS WELL... KEEP PLAYING!!!
Whenever you feel that my post really helped you to learn something new, please press on the 'THANK' button.
